JayJay's Playground

[gstyle]

As promised :wink:

RN WKLV VKRXOG EH HDVB LWV D VLPSOH FDHVDU FLSKHU

[Jay Jay]

As promised :wink:

RN WKLV VKRXOG EH HDVB LWV D VLPSOH FDHVDU FLSKHU

:clap: JRW LW! :na: ............WKDQNV IRU ORYBOB GDQFHV :nice:

[gstyle]

Pb Sohdvxuh Oryhob Mdbmdb...wkdw Odvw Rqh Zdv Wrr Hdvb

[Jay Jay]

Pb Sohdvxuh Oryhob Mdbmdb...wkdw Odvw Rqh Zdv Wrr Hdvb

vpdoo fkdqjh wkhq:wink:

..............szap jzf slgp l rzzo hppv

[JiveLad]

Ok - so it's a simple 4 letter displacement 'Ceasar' cipher............

It took about 30 secs to decipher. The first clue was the single letter.....'D' - a bit of a giveaway..........

Except the final message was a 13 letter displacement.

I called up my friend from Bletchley Park who dusted off their Enigma machine for the last message as it was a bit trickier....


....err42 kw eeaz ilm!

[Jay Jay]

Ok - so it's a simple 4 letter displacement 'Ceasar' cipher............

It took about 30 secs to decipher. The first clue was the single letter.....'D' - a bit of a giveaway..........

Look Jivelad....it's first thing on a Monday morning and I was dancing last night and I have a meeting to prepare and chores to do plus if it's too hard I'll give up anyway so :na: (meant in a caring way :hug:)
xx

[gstyle]

01010000010110100
01000000100000101
00111101010000010
11010001000000100
10000101010101000
11000100000010011
11010010000101100
10100101101001100
01011001

[Jay Jay]

01010000010110100
01000000100000101
00111101010000010
11010001000000100
10000101010101000
11000100000010011
11010010000101100
10100101101001100
01011001

:what: OMG...you might have to give me a while on this one........are you sure it's not an international phone number?

[Jay Jay]

0100010001010110
0100010000100000
0100100101000010
0100000100100000
0100111001010110
0100000100100000
0100000101001111
0100110001011001
01001100

:-)) :-))

[Jay Jay]

tirzyetthhiesnomnaetfeoyr.s

:grin:

[gstyle]

I did, and you know what, it was the perfect fit! :waycool:

[gstyle]

Gd Dd Df Ga Df Ga Ga Dx Df Ga Dd Gd Dx Va Ag Df Ax Ax Av Fx Av Fd Gd

[stewart38]

Gd Dd Df Ga Df Ga Ga Dx Df Ga Dd Gd Dx Va Ag Df Ax Ax Av Fx Av Fd Gd

Is that the answer ?

[David Franklin]

Gd Dd Df Ga Df Ga Ga Dx Df Ga Dd Gd Dx Va Ag Df Ax Ax Av Fx Av Fd GdI don't think you can spell "Ga Dx Df Da Dd Gd Dx Va" properly...

[gstyle]

Is that the answer ?

No it is a new cipher.

The answer to the binary I posted was that the message simply read 'IS THIS ANY HARDER'. It was a binary conversation followed by an 8 shift caesar cipher.

JayJay worked this out and replied with a binary conversation followed by a 19 shift caesar cipher. Her message was 'WOW BUT GOT THERE'.

JayJay followed again with an anagram which I replied to. Anagram reads 'Then try this on for size matey'.

The line of letters 'GD DD DF etc' is the next ciphertext.

Ummmm as pointed out by David Frankin I have one of the ciphers wrong, so I now trying to work out how to edit my post :whistle::blush: Anyway still should be able to get the message even with one cipher out.

[David Franklin]

Hint: pq=851, e=5, message is 42 characters long

715 93 357 540 506 465 448 225 348 436 369 32 492 487 225 815 653 52 712 749 700

[Jay Jay]

Hint: pq=851, e=5, message is 42 characters long

715 93 357 540 506 465 448 225 348 436 369 32 492 487 225 815 653 52 712 749 700




:tears::tears::tears::tears:...think I am getting out of my depth but will try to solve this one, tho I must say I am very proud of myself for solving the others didn't know I had it in me!

[David Franklin]

:tears::tears::tears::tears:...think I am getting out of my depth but will try to solve this one, tho I must say I am very proud of myself for solving the othersdidn't know I had it in me!If the hint means nothing to you, it's probably not worth bothering with, to be honest. I was just curious to see who'd jump for the bait.

[Jay Jay]

If the hint means nothing to you, it's probably not worth bothering with, to be honest. I was just curious to see who'd jump for the bait.

I will not be defeated................thanks for the hint of the hint, I shall get back to the drawing board...in between real work that is :wink:

[David Franklin]

I will not be defeated................thanks for the hint of the hint, I shall get back to the drawing board...in between real work that is :wink:Just in case my hint might be misleading you: pq=851, e=5 is not a hint about what "pq" and "e" encode to, it specifies the parameters to a reasonably well known encryption system.

[gstyle]

I am now assuming this is RSA encryption algorithm. Using pq=851 as the public key and e=5 as the public key exponent?

I hate maths.

You dont want to tell me the two prime numbers you used to get pq do you :confused:

[Jay Jay]

I am on the trail boys.....just need the time to sit with it a while....still not giving up :D

........have to say when I saw you made me a 'playground' didn't think it would be this hard!

[David Franklin]

I am now assuming this is RSA encryption algorithm. Using pq=851 as the public key and e=5 as the public key exponent?Correct.


You dont want to tell me the two prime numbers you used to get pq do you :confused:If you really want, but they are quite easy to find by guesswork.

But assuming you're going to use a computer, pq is so small here that it's easy to brute-force the decryption exponent without needing to go through the steps relying on factorizing 851.

[gstyle]

Ah ha so I am thinking 23 and 37 are the prime numbers. The totient is 792...so now I have to work out e * d = 1 (mod (792)) .

Did I mention I really hate maths :angry:

[Jay Jay]

Ah ha so I am thinking 23 and 37 are the prime numbers. The totient is 792...so now I have to work out e * d = 1 (mod (792)) .

Did I mention I really hate maths :angry:

Thanks for doing the ground work for me, if I sit back and wait you can give me the answer aswell :wink: